3.160 \(\int \frac{A+B x}{x^3 (a+b x)^2} \, dx\)

Optimal. Leaf size=85 \[ \frac{b \log (x) (3 A b-2 a B)}{a^4}-\frac{b (3 A b-2 a B) \log (a+b x)}{a^4}+\frac{2 A b-a B}{a^3 x}+\frac{b (A b-a B)}{a^3 (a+b x)}-\frac{A}{2 a^2 x^2} \]

[Out]

-A/(2*a^2*x^2) + (2*A*b - a*B)/(a^3*x) + (b*(A*b - a*B))/(a^3*(a + b*x)) + (b*(3
*A*b - 2*a*B)*Log[x])/a^4 - (b*(3*A*b - 2*a*B)*Log[a + b*x])/a^4

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Rubi [A]  time = 0.163731, antiderivative size = 85, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.062 \[ \frac{b \log (x) (3 A b-2 a B)}{a^4}-\frac{b (3 A b-2 a B) \log (a+b x)}{a^4}+\frac{2 A b-a B}{a^3 x}+\frac{b (A b-a B)}{a^3 (a+b x)}-\frac{A}{2 a^2 x^2} \]

Antiderivative was successfully verified.

[In]  Int[(A + B*x)/(x^3*(a + b*x)^2),x]

[Out]

-A/(2*a^2*x^2) + (2*A*b - a*B)/(a^3*x) + (b*(A*b - a*B))/(a^3*(a + b*x)) + (b*(3
*A*b - 2*a*B)*Log[x])/a^4 - (b*(3*A*b - 2*a*B)*Log[a + b*x])/a^4

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Rubi in Sympy [A]  time = 30.1712, size = 80, normalized size = 0.94 \[ - \frac{A}{2 a^{2} x^{2}} + \frac{b \left (A b - B a\right )}{a^{3} \left (a + b x\right )} + \frac{2 A b - B a}{a^{3} x} + \frac{b \left (3 A b - 2 B a\right ) \log{\left (x \right )}}{a^{4}} - \frac{b \left (3 A b - 2 B a\right ) \log{\left (a + b x \right )}}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((B*x+A)/x**3/(b*x+a)**2,x)

[Out]

-A/(2*a**2*x**2) + b*(A*b - B*a)/(a**3*(a + b*x)) + (2*A*b - B*a)/(a**3*x) + b*(
3*A*b - 2*B*a)*log(x)/a**4 - b*(3*A*b - 2*B*a)*log(a + b*x)/a**4

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Mathematica [A]  time = 0.131025, size = 85, normalized size = 1. \[ \frac{-\frac{a \left (a^2 (A+2 B x)+a b x (4 B x-3 A)-6 A b^2 x^2\right )}{x^2 (a+b x)}+2 b \log (x) (3 A b-2 a B)+2 b (2 a B-3 A b) \log (a+b x)}{2 a^4} \]

Antiderivative was successfully verified.

[In]  Integrate[(A + B*x)/(x^3*(a + b*x)^2),x]

[Out]

(-((a*(-6*A*b^2*x^2 + a^2*(A + 2*B*x) + a*b*x*(-3*A + 4*B*x)))/(x^2*(a + b*x)))
+ 2*b*(3*A*b - 2*a*B)*Log[x] + 2*b*(-3*A*b + 2*a*B)*Log[a + b*x])/(2*a^4)

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Maple [A]  time = 0.016, size = 107, normalized size = 1.3 \[ -{\frac{A}{2\,{a}^{2}{x}^{2}}}+2\,{\frac{Ab}{{a}^{3}x}}-{\frac{B}{{a}^{2}x}}+3\,{\frac{A\ln \left ( x \right ){b}^{2}}{{a}^{4}}}-2\,{\frac{bB\ln \left ( x \right ) }{{a}^{3}}}-3\,{\frac{{b}^{2}\ln \left ( bx+a \right ) A}{{a}^{4}}}+2\,{\frac{b\ln \left ( bx+a \right ) B}{{a}^{3}}}+{\frac{A{b}^{2}}{{a}^{3} \left ( bx+a \right ) }}-{\frac{Bb}{{a}^{2} \left ( bx+a \right ) }} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((B*x+A)/x^3/(b*x+a)^2,x)

[Out]

-1/2*A/a^2/x^2+2/a^3/x*A*b-1/a^2/x*B+3*b^2/a^4*ln(x)*A-2*b/a^3*ln(x)*B-3*b^2/a^4
*ln(b*x+a)*A+2*b/a^3*ln(b*x+a)*B+1/a^3*b^2/(b*x+a)*A-1/a^2*b/(b*x+a)*B

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Maxima [A]  time = 1.33854, size = 134, normalized size = 1.58 \[ -\frac{A a^{2} + 2 \,{\left (2 \, B a b - 3 \, A b^{2}\right )} x^{2} +{\left (2 \, B a^{2} - 3 \, A a b\right )} x}{2 \,{\left (a^{3} b x^{3} + a^{4} x^{2}\right )}} + \frac{{\left (2 \, B a b - 3 \, A b^{2}\right )} \log \left (b x + a\right )}{a^{4}} - \frac{{\left (2 \, B a b - 3 \, A b^{2}\right )} \log \left (x\right )}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)^2*x^3),x, algorithm="maxima")

[Out]

-1/2*(A*a^2 + 2*(2*B*a*b - 3*A*b^2)*x^2 + (2*B*a^2 - 3*A*a*b)*x)/(a^3*b*x^3 + a^
4*x^2) + (2*B*a*b - 3*A*b^2)*log(b*x + a)/a^4 - (2*B*a*b - 3*A*b^2)*log(x)/a^4

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Fricas [A]  time = 0.212768, size = 203, normalized size = 2.39 \[ -\frac{A a^{3} + 2 \,{\left (2 \, B a^{2} b - 3 \, A a b^{2}\right )} x^{2} +{\left (2 \, B a^{3} - 3 \, A a^{2} b\right )} x - 2 \,{\left ({\left (2 \, B a b^{2} - 3 \, A b^{3}\right )} x^{3} +{\left (2 \, B a^{2} b - 3 \, A a b^{2}\right )} x^{2}\right )} \log \left (b x + a\right ) + 2 \,{\left ({\left (2 \, B a b^{2} - 3 \, A b^{3}\right )} x^{3} +{\left (2 \, B a^{2} b - 3 \, A a b^{2}\right )} x^{2}\right )} \log \left (x\right )}{2 \,{\left (a^{4} b x^{3} + a^{5} x^{2}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)^2*x^3),x, algorithm="fricas")

[Out]

-1/2*(A*a^3 + 2*(2*B*a^2*b - 3*A*a*b^2)*x^2 + (2*B*a^3 - 3*A*a^2*b)*x - 2*((2*B*
a*b^2 - 3*A*b^3)*x^3 + (2*B*a^2*b - 3*A*a*b^2)*x^2)*log(b*x + a) + 2*((2*B*a*b^2
- 3*A*b^3)*x^3 + (2*B*a^2*b - 3*A*a*b^2)*x^2)*log(x))/(a^4*b*x^3 + a^5*x^2)

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Sympy [A]  time = 4.58925, size = 184, normalized size = 2.16 \[ - \frac{A a^{2} + x^{2} \left (- 6 A b^{2} + 4 B a b\right ) + x \left (- 3 A a b + 2 B a^{2}\right )}{2 a^{4} x^{2} + 2 a^{3} b x^{3}} - \frac{b \left (- 3 A b + 2 B a\right ) \log{\left (x + \frac{- 3 A a b^{2} + 2 B a^{2} b - a b \left (- 3 A b + 2 B a\right )}{- 6 A b^{3} + 4 B a b^{2}} \right )}}{a^{4}} + \frac{b \left (- 3 A b + 2 B a\right ) \log{\left (x + \frac{- 3 A a b^{2} + 2 B a^{2} b + a b \left (- 3 A b + 2 B a\right )}{- 6 A b^{3} + 4 B a b^{2}} \right )}}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x+A)/x**3/(b*x+a)**2,x)

[Out]

-(A*a**2 + x**2*(-6*A*b**2 + 4*B*a*b) + x*(-3*A*a*b + 2*B*a**2))/(2*a**4*x**2 +
2*a**3*b*x**3) - b*(-3*A*b + 2*B*a)*log(x + (-3*A*a*b**2 + 2*B*a**2*b - a*b*(-3*
A*b + 2*B*a))/(-6*A*b**3 + 4*B*a*b**2))/a**4 + b*(-3*A*b + 2*B*a)*log(x + (-3*A*
a*b**2 + 2*B*a**2*b + a*b*(-3*A*b + 2*B*a))/(-6*A*b**3 + 4*B*a*b**2))/a**4

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GIAC/XCAS [A]  time = 0.424267, size = 176, normalized size = 2.07 \[ -\frac{{\left (2 \, B a b^{2} - 3 \, A b^{3}\right )}{\rm ln}\left ({\left | -\frac{a}{b x + a} + 1 \right |}\right )}{a^{4} b} - \frac{\frac{B a b^{4}}{b x + a} - \frac{A b^{5}}{b x + a}}{a^{3} b^{3}} - \frac{2 \, B a b - 5 \, A b^{2} - \frac{2 \,{\left (B a^{2} b^{2} - 3 \, A a b^{3}\right )}}{{\left (b x + a\right )} b}}{2 \, a^{4}{\left (\frac{a}{b x + a} - 1\right )}^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((B*x + A)/((b*x + a)^2*x^3),x, algorithm="giac")

[Out]

-(2*B*a*b^2 - 3*A*b^3)*ln(abs(-a/(b*x + a) + 1))/(a^4*b) - (B*a*b^4/(b*x + a) -
A*b^5/(b*x + a))/(a^3*b^3) - 1/2*(2*B*a*b - 5*A*b^2 - 2*(B*a^2*b^2 - 3*A*a*b^3)/
((b*x + a)*b))/(a^4*(a/(b*x + a) - 1)^2)